![SOLVED:The molar enthalpy change for the neutralization reaction: HCI (aq) + NaOH (aq) +> NaCl (aq) + HzO (I) is AH=-57.3 k/mol. This is an exothermic reaction which means heat is released. SOLVED:The molar enthalpy change for the neutralization reaction: HCI (aq) + NaOH (aq) +> NaCl (aq) + HzO (I) is AH=-57.3 k/mol. This is an exothermic reaction which means heat is released.](https://cdn.numerade.com/ask_images/7fd52345320748af9aa947bf611fa5e1.jpg)
SOLVED:The molar enthalpy change for the neutralization reaction: HCI (aq) + NaOH (aq) +> NaCl (aq) + HzO (I) is AH=-57.3 k/mol. This is an exothermic reaction which means heat is released.
Experiment: To measure the molar enthalpy change for the dissolution ( enthalpy of solution) for vari - Tutorke
![The molar enthalpy of neutralization was experimentary shown to be 51.5kJ per mole of 0.5M hydrochloric acid and 0.5M sodium hydroxide. If the volume of... The molar enthalpy of neutralization was experimentary shown to be 51.5kJ per mole of 0.5M hydrochloric acid and 0.5M sodium hydroxide. If the volume of...](https://www.kenyaplex.com/questions/uploads/vol11922019550.png)